反应 #828714

ord-03132c9ab6a2405cb9ba4e9ebe56e992

反应方程式

CCOC(=O)C1=Cc2c3nc(cc4[nH]c(cc5[nH]c(cc6nc2C1(CC)C6CC)c(CC)c5CC)c(CC)c4CC)C(CC)=C3CC
Purpurin NT2
C1=Cc2cc3ccc(cc4nc(cc5ccc(cc1n2)[nH]5)C=C4)[nH]3
porphyrin

反应物

试剂

反应条件

详细条件
See reaction.notes.procedure_details.

后处理

  1. 1
    其他to stand for a total of 16 hours in sunlight, in contact with air
  2. 2
    其他under ambient conditions (temperature about 22°)
  3. 3
    其他The dichloromethane was then removed by evaporation

实验过程

A 50 mg portion of Purpurin NT2 was dissolved in 20 ml dichloromethane, and the resulting solution was allowed to stand for a total of 16 hours in sunlight, in contact with air, and under ambient conditions (temperature about 22°). The dichloromethane was then removed by evaporation, leaving 50 mg porphyrin derivative (hereafter "Porphyrin NT2") which was found by nuclear magnetic resonance to have the formula of FIG. 7 of the attached drawings where R1 through R8 are ethyl, R10 through R12 are hydrogen, and R13 is CH2CH3. The production of Purpurin NT2 is described in Example 1 of PCT/US86/02824; it has the formula of FIG. 5 of the drawings of that application where R1 through R8 are ethyl, R9 is CO2CH2CH3, and R10 through R13 are hydrogen.

来源

DOI: 10.6084/m9.figshare.5104873.v1专利: US05552134uspto-grants-1996_09