反应 #749415

ord-5ce05d6fdf0b435e9ea46803ad2c59d4

反应方程式

O=C(NCCC1CC1)c1ccc(N2CCNCC2)nn1
O=C(NCCC1CC1)c1ccc(N
CC(O)(CC(=O)O)C(F)(F)F
CC(O)(CC(=O)O)C(F)(F
CC(O)(CC(=O)N1CCN(c2ccc(C(=O)NCCC3CC3)nn2)CC1)C(F)(F)F
CC(O)(CC(=O)N1CCN(c2

来源

DOI: 10.1039/C8SC04228DTraining data from https://doi.org/10.1039/C8SC04228D (3/10)