反应 #465958
ord-7c6086651c14412d9ff26ab9dd4627c3
反应方程式
H2O NH4OH
lithium aluminum hydride
methyl 6-bromo-3-chloro-4-nitropyridine-2-carboxylate
→
methyl 4-amino-6-bromo-3-chloropyridine-2-carboxylate
反应条件
详细条件
See reaction.notes.procedure_details.
后处理
- 1workup.STIRRINGThe solution was stirred 1 hr
- 2过滤filtering
- 3萃取The filtrate was extracted with EtOAc (2×75 mL)
- 4干燥The organic phase was dried (Na2SO4)
- 5浓缩concentrated
- 6其他The red solid was chromatographed over silica in 4:1 EtOAc/hexane
实验过程
To a solution of titanium tetrachloride (0.015 mol, 2.8 g) in tetrahydrofuran (50 mL) was added lithium aluminum hydride (0.0175 mol, 0.7 g). The black slurry was stirred 15 min before adding methyl 6-bromo-3-chloro-4-nitropyridine-2-carboxylate, N-oxide (0.007 mol, 2.3 g) in THF (25 mL). The solution was stirred 1 hr before pouring into 1:1 H2O/NH4OH and filtering. The filtrate was extracted with EtOAc (2×75 mL). The organic phase was dried (Na2SO4), and concentrated. The red solid was chromatographed over silica in 4:1 EtOAc/hexane to give methyl 4-amino-6-bromo-3-chloropyridine-2-carboxylate (0.003 mol, 0.8 g); mp 194-5° C. 1H NMR(CDCl3): δ 3.95 (3H, s), 5.3 (2H, bs), 6.9 (1H, s).