反应 #2171056

反应方程式

hydrochloric acid

( 1 )

4-(5-Chloroindol-3-yl)-2-methylamino-4-oxo-2-butenoic acid ethyl ester

NaOH

→

titled compound

收率 80.0%

4-(5-Chloroindol-3-yl)-2-methylamino-4oxo-2-butenoic acid

收率 80.0%

溶剂

dioxane

反应条件

后处理

1. 1
   浓缩concentrated under reduced pressure
2. 2
   workup.ADDITIONThe residue was diluted with water
3. 3
   过滤The obtained crystal was collected by filtration
4. 4
   洗涤washed with water and 95% EtOH

实验过程

To a solution of 0.22 g of the ester described in above (1) in dioxane (2.2 ml) was added 1 N NaOH (0.9 ml). After stirring for 2 hours, the mixture was treated with 1 N hydrochloric acid (0.9 ml), and concentrated under reduced pressure. The residue was diluted with water. The obtained crystal was collected by filtration, and washed with water and 95% EtOH to give 0.15 g of the titled compound. Yield: 80%.

来源