反应 #215064

ord-d9b6e7c959d04d14973519fa3b99291d

反应方程式

O=S(=O)([O-])[O-]
sulfate
O=P([O-])([O-])[O-].O=P([O-])([O-])[O-].O=P([O-])([O-])[O-].[Ca+2].[Ca+2].[Ca+2].[Ca+2].[Ca+2].[F-]
phosphate rock
[Ca]
calcium
O=S(=O)(O)O
Sulfuric acid
O=S(=O)([O-])[O-]
sulfate
O=S(=O)([O-])[O-]
sulfate
→
O.O=S(=O)([O-])[O-].O=S(=O)([O-])[O-].[Ca+2].[Ca+2]
calcium sulfate hemihydrate

反应物

O=S(=O)([O-])[O-]
sulfate
O=P([O-])([O-])[O-].O=P([O-])([O-])[O-].O=P([O-])([O-])[O-].[Ca+2].[Ca+2].[Ca+2].[Ca+2].[Ca+2].[F-]
phosphate rock
[Ca]
calcium
O=S(=O)(O)O
Sulfuric acid
O=S(=O)([O-])[O-]
sulfate
O=S(=O)([O-])[O-]
sulfate

试剂

无

反应条件

详细条件
See reaction.notes.procedure_details.

实验过程

Sulfuric acid is added in amounts such that the sulfate content of the added acid and the sulfate content of the added rock is equivalent to about 90% to about 100% (more preferred 93-99.5%) of the stoichiometric amount of sulfate required to react with calcium added in the phosphate rock to form calcium sulfate hemihydrate.

来源

DOI: 10.6084/m9.figshare.5104873.v1专利: US04258007uspto-grants-1981_03