反应 #1951035

反应方程式

MeOH CHCl3

3-Formyl-2,5,6-trichloro-1-[3,5-di-O-(p-toluoyl)-2-deoxy-β-D-ribofuranosyl]indole

sodium methoxide

→

4.114

收率 69.0%

5,6-Dichloro-2-methoxy-3-formyl-1-(2-deoxy-β-D-ribofuranosyl)indole

收率 69.0%

溶剂

MeOH

MeOH

反应条件

后处理

1. 1
   其他The solvent was then removed under vacuum
2. 2
   萃取extracted with EtOAc (2×100 mL)
3. 3
   洗涤The combined organic extracts were washed with brine (25 mL)
4. 4
   干燥dried over MgSO4
5. 5
   过滤filtered
6. 6
   其他evaporated
7. 7
   其他to yield a damp solid
8. 8
   workup.ADDITIONFractions containing product
9. 9
   其他evaporated
10. 10
    其他to yield a white solid
11. 11
    其他The solid was recrystallized
12. 12
    温度from warm MeOH

实验过程

3-Formyl-2,5,6-trichloro-1-[3,5-di-O-(p-toluoyl)-2-deoxy-β-D-ribofuranosyl]indole (4.113, 198 mg, 0.33 mmol) was suspended in dry MeOH (10 mL) to which was added sodium methoxide (75 mg, 1.4 mmol). The suspension was stirred at room temperature for 16 h, after which time the solution clarified. The solvent was then removed under vacuum, and the residue was suspended in water (50 mL), and extracted with EtOAc (2×100 mL). The combined organic extracts were washed with brine (25 mL), dried over MgSO4, filtered and evaporated to yield a damp solid. The crude material was dissolved in MeOH (1 mL) and subjected to column chromatography (40×350 mm) on silica gel with 10% MeOH/CHCl3. Fractions containing product were pooled and evaporated to yield a white solid. The solid was recrystallized from warm MeOH to yield 82 mg (68%) of 4.114 as a white crystalline solid: mp 186-187° C.; Rf0.3 (10% MeOH/CHCl3); 1H-NMR (500 MHz, DMSO-d6): δ 10.21 (s, 1H), 8.29 (s, 1H), 8.22 (s, 1H), 6.32 (dd, 1H), 5.37 (b, 1H, D2O exch.), 5.15 (b, 1H, D2O exch.), 4.43 (s, 3H), 4.41 (m, 1H), 3.83 (d, 1H), 3.68 (m, 2H), 2.53 (m, 1H), 2.11 (m, 1H). 13C-NMR (125 MHz, DMSO-d6): δ 183.22, 159.16, 129.40, 125.04, 124.73, 124.66, 121.11, 114.24, 100.02, 87.29, 82.99, 70.07, 64.16, 61.03, 38.43. HRMS (EI) m/z calcd. for C15H15Cl2NO5 359.0327, found 359.0320. Anal calcd for C15H15Cl2NO5.½H2O: C, 48.80; H, 4.37; N, 3.79. Found: C, 48.48; H, 4.61; N, 3.61.

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