反应 #1869149

ord-f4736c1983ad4437920881e9356b17a0

反应方程式

C=CCCCCCCCCC(=O)O
10-undecenoic acid
O=C(Cl)C(=O)Cl
(COCl)2
C=CCCCCCCCCC(=O)Cl
10-undecenoyl chloride
收率 100.0%

试剂

溶剂

反应条件

详细条件
See reaction.notes.procedure_details.

后处理

  1. 1
    其他The solvent was removed under reduced pressure

实验过程

To a stirred solution of 10-undecenoic acid (5.055 mL, 25 mmol) in CH2Cl2 (50 mL) was slowly added (COCl)2 (4.364 mL, 50 mmol). The mixture was stirred at room temperature overnight. The solvent was removed under reduced pressure to give 10-undecenoyl chloride (25 mmol). The product was used for the next reaction without further purification. 1H NMR (500 MHz, CDCl3) δ 1.29-1.48 (m, 10H), 1.71 (m, 2H), 2.05 (m, 2H), 2.88 (t, J=7 Hz, 2H), 4.98 (m, 2H), 5.80 (m, 1H).

来源

DOI: 10.6084/m9.figshare.5104873.v1专利: US07498292B2uspto-grants-2009_03