反应 #1622413

ord-67a89bfc6bf840d7b31bab7045ca6732

反应方程式

[Br-]
[Br-]
O=C(Cl)Oc1ccc(C(=O)NCCc2ccc(Cl)cc2)cc1
O=C(Cl)Oc1ccc(C(=O)N
[K+]
[K+]
C1COC(CN2CCNCC2)C1
C1COC(CN2CCNCC2)C1
O=C(NCCc1ccc(Cl)cc1)c1ccc(OC(=O)N2CCN(CC3CCCO3)CC2)cc1
O=C(NCCc1ccc(Cl)cc1)

来源

DOI: 10.1039/C8SC04228DTraining data from https://doi.org/10.1039/C8SC04228D (1/10)