反应 #1238

反应方程式

7-(1-adamantyl)-6-hydroxy-2-bromonaphthalene

4-fluorobenzyl bromide

→

expected compound

收率 86.0%

7-(1-adamantyl)-6-(4-fluorobenzyl)oxy-2-bromonaphthalene

收率 86.0%

反应条件

实验过程

Following the basic procedure of Example 11, by reacting 1.1 g (3 mmol) of 7-(1-adamantyl)-6-hydroxy-2-bromonaphthalene with 420 μl (3,3 mmol) of 4-fluorobenzyl bromide, 1.2 g (86%) of the expected compound was obtained in the form of a colorless oil.

来源