反应 #1199976

ord-0fd2cb77116a48e5ad56c4f7d45d2ab2

反应方程式

O=C(NCCC1CC1)c1ccc(Cl)nn1
O=C(NCCC1CC1)c1ccc(C
Fc1ccc(N2CCNCC2)cc1
Fc1ccc(N2CCNCC2)cc1
FC(F)(F)c1cccc(N2CCNCC2)c1
FC(F)(F)c1cccc(N2CCN
O=C(NCCC1CC1)c1ccc(N2CCN(c3cccc(C(F)(F)F)c3)CC2)nn1
O=C(NCCC1CC1)c1ccc(N

来源

DOI: 10.1039/C8SC04228DTraining data from https://doi.org/10.1039/C8SC04228D (7/10)