Реакция #939014

Уравнение реакции

1-n-butyl-3-methylimidazolium chloride

sodium lauryl sulfate

→

product

Выход 94.2%

1-n-Butyl-3-methylimidazolium Lauryl Sulfate

Выход 94.2%

Растворители

water

Условия реакции

Обработка

1. 1
   ДругоеThe water is slowly removed under vacuum
2. 2
   ДругоеThe solid formed
3. 3
   Фильтрацияis filtered off
4. 4
   workup.ADDITIONafter adding methylene chloride to the batch
5. 5
   ПромывкаThe filtrate is washed with water until the aqueous phase
6. 6
   СушкаThe organic phase is dried over Na2SO4
7. 7
   КонцентрированиеConcentrating
8. 8
   Другоеdrying under a high vacuum

Методика

15.30 g (87.6 mmole) of 1-n-butyl-3-methylimidazolium chloride (BMIM Cl) and 26.60 g (minimum 87.6 mmole) of sodium lauryl sulfate (technical grade, content 95-99%) are dissolved in 50 ml of hot water. The water is slowly removed under vacuum. The solid formed is filtered off after adding methylene chloride to the batch. The filtrate is washed with water until the aqueous phase is colourless and free from chloride. The organic phase is dried over Na2SO4. Concentrating and drying under a high vacuum gives 33.40 g of product (82.5 mmole; 94% of the theoretical yield, based on BMIM Cl) which is obtained as a white beige waxy solid.

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