Реакция #801841

Уравнение реакции

compound

5-(4-Chlorophenyl)-4-[(2S)-3,3,3-trifluoro-2-hydroxypropyl]-2,4-dihydro-3H-1,2,4-triazol-3-one

1-bromo-3-(bromomethyl)-5-fluorobenzene

→

2-(3-Bromo-5-fluorobenzyl)-5-(4-chlorophenyl)-4-[(2S)-3,3,3-trifluoro-2-hydroxypropyl]-2,4-dihydro-3H-1,2,4-triazol-3-one

Условия реакции

Методика

219 mg (0.71 mmol) of the compound from Example 5A and 191 mg (0.71 mmol) of 1-bromo-3-(bromomethyl)-5-fluorobenzene were reacted analogously to the preparation of Example 101A. This gave 181 mg (51% of theory) of the target compound.

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