Реакция #77793

Уравнение реакции

NaOH

NaCNBH3

5-(6-Fluoro-1H-indol-5-yl)-pent-4-yn-1-ol

water

→

5-(6-Fluoro-2,3-dihydro-1H-indol-5-yl)-pent-4-yn-1-ol

Выход 73.0%

Растворители

AcOH TFA

Условия реакции

Обработка

1. 1
   Экстракцияextracted with EtOAc
2. 2
   СушкаDrying of the combined organic layers with MgSO4, evaporation of the solvent, and chromatography on silica gel with CH2Cl2/MeOH 49:1

Методика

A solution of 109 mg (0.5 mmol) 5-(6-Fluoro-1H-indol-5-yl)-pent-4-yn-1-ol in 3 ml AcOH/TFA 2:1 was cooled to 0° C., treated with NaCNBH3 and stirred for 1 hour at room temperature. The mixture was poured into icy water, made strongly alkaline by the addition of 2M NaOH, and extracted with EtOAc. Drying of the combined organic layers with MgSO4, evaporation of the solvent, and chromatography on silica gel with CH2Cl2/MeOH 49:1 gave 80 mg (73%) of 5-(6-Fluoro-2,3-dihydro-1H-indol-5-yl)-pent-4-yn-1-ol as a colorless oil, MS: 220 (MH+).

Источник