Реакция #727991

ord-9c68496a70834183bfc4ac8812e4bf27

Уравнение реакции

Cl
HCl
CCOC=O
Ethyl formate
CCOC(=O)Cc1ccc(Cl)cc1
(4-chlorophenyl)acetic acid ethyl ester
[H-].[Na+]
NaH
CCOC(=O)C(C=O)c1ccc(Cl)cc1
2-(4-chlorophenyl)-3-oxo-propanoic acid ethyl ester
Выход 87.0%

Растворители

Условия реакции

Подробные условия
See reaction.notes.procedure_details.

Обработка

  1. 1
    Температураcooled
  2. 2
    Другоеthe organic layer was isolated
  3. 3
    Другоеdried
  4. 4
    Другоеthe solvent removed

Методика

Ethyl formate (7.46 g, 0.101 mol) was added dropwise to a stirred ice-cooled suspension of (4-chlorophenyl)acetic acid ethyl ester (20.0 g, 0.101 mol) and NaH (0.131 mol) in diethyl ether (100 mL). The mixture was then allowed to warm to room temperature overnight. The mixture neutralised (1 M HCl); the organic layer was isolated, dried, and the solvent removed to give 2-(4-chlorophenyl)-3-oxo-propanoic acid ethyl ester as a colourless solid (19.8 g, 87%). 1H NMR (CDCl3): δ 12.14 (d, J=12.8, 1H), 7.31-7.18 (m, 4H), 4.29 (q, J=7.2, 2H), 1.57 (br, 1H), 1.29 (t, J=7.2, 3H).

Источник

DOI: 10.6084/m9.figshare.5104873.v1Патент: US07692011B2uspto-grants-2010_04