Реакция #727991
ord-9c68496a70834183bfc4ac8812e4bf27
Уравнение реакции
HCl
Ethyl formate
(4-chlorophenyl)acetic acid ethyl ester
NaH
→
2-(4-chlorophenyl)-3-oxo-propanoic acid ethyl ester
Выход 87.0%
Реагенты
Нет
Растворители
Условия реакции
Подробные условия
See reaction.notes.procedure_details.
Обработка
- 1Температураcooled
- 2Другоеthe organic layer was isolated
- 3Другоеdried
- 4Другоеthe solvent removed
Методика
Ethyl formate (7.46 g, 0.101 mol) was added dropwise to a stirred ice-cooled suspension of (4-chlorophenyl)acetic acid ethyl ester (20.0 g, 0.101 mol) and NaH (0.131 mol) in diethyl ether (100 mL). The mixture was then allowed to warm to room temperature overnight. The mixture neutralised (1 M HCl); the organic layer was isolated, dried, and the solvent removed to give 2-(4-chlorophenyl)-3-oxo-propanoic acid ethyl ester as a colourless solid (19.8 g, 87%). 1H NMR (CDCl3): δ 12.14 (d, J=12.8, 1H), 7.31-7.18 (m, 4H), 4.29 (q, J=7.2, 2H), 1.57 (br, 1H), 1.29 (t, J=7.2, 3H).