Реакция #67391
ord-e9ec76f82cd648198c7032390589201c
Уравнение реакции
Реагенты
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Условия реакции
Обработка
- 1workup.ADDITIONThe orange solution was added dropwise to
- 2Другоеthe solvent then removed in vacuo
- 3Другоеleaving purple oil
- 4Другоеto give a cloudy white mixture, which
- 5Экстракцияwas extracted with deionized water (5×100 mL)
- 6СушкаThe yellow organic layer was dried over Na2SO4
- 7Другоеthe solids were then separated by filtration
- 8ДругоеSolvent was removed from the filtrate in vacuo
- 9Другоеto leave a pale yellow oil which
Методика
A solution of n-butyllithium (100.0 mL, 1.6 M, 0.161 mol) in hexanes was added dropwise to a cooled (0° C.) solution of fluorene (26.75 g, 0.161 mol) in 200 mL of diethyl ether. The reaction solution turned orange and was warmed to 25° C. for 30 minutes. The orange solution was added dropwise to a cooled (0° C.) solution of bromoacetaldehyde diethylacetal (25.0 mL, 0.161 mol) in 50 mL of diethyl ether. The reaction solution was stirred for 12 hours and the solvent then removed in vacuo leaving purple oil. Methylene chloride (300 mL) was added to the residue to give a cloudy white mixture, which was extracted with deionized water (5×100 mL). The yellow organic layer was dried over Na2SO4 and the solids were then separated by filtration. Solvent was removed from the filtrate in vacuo to leave a pale yellow oil which solidified to a yellow waxy solid upon standing. Yield: 42.2 g, 0.149 mol (93%). 1H NMR (CDCl3, 600 MHz): δ 7.73 (d, 3JHH=7.8 Hz, 2H, flu-H4), 7.54 (d, 3JHH=7.8 Hz, 2H, flu-H1), 7.34 (t, 3JHH=7.2 Hz, 2H, flu-H3), 7.28 (t, 3JHH=7.2 Hz, 2H, flu-H2), 4.69 (t, 3JHH=6.0 Hz, 1H, CH), 4.08 (t, 3JHH=7.2 Hz, 1H, flu-CH), 3.52 (dm, 4H, OCH2CH3), 2.21 (dd, 2H, CH2), 1.13 (t, 3JHH=7.2 Hz, 6H, OCH2CH3). 13C{1H} NMR (CDCl3, 150.8 MHz): 147.25 (s, C1-a), 140.81 (s, C4a), 126.96 (s, C2), 126.82 (s, C3), 124.73 (s, C1), 119.78 (s, C4), 101.41 (s, CH), 61.45 (s, OCH2CH3), 43.93 (s, C9), 37.49 (s, CH2), 15.27 (s, OCH2CH3). MS (ES) m/z (assignment, relative intensity): 305.2 (C19H22O2Na, [M+Na]+, 100%). Anal. Calcd. for C19H22O2: C, 80.82; H, 7.85. Found: C, 80.89; H, 8.09.