Реакция #66912

Уравнение реакции

Compound 22

7-Benzyloxy-2-(2-fluorophenyl)-6-methoxyquinolin-4-one

compound 40

2-(2-Fluorophenyl)-5,6-dihydroxyquinolin-4-one

→

43

Выход 61.3%

2-(2-Fluorophenyl)-7-hydroxy-6-methoxyquinolin-4-one

Выход 61.3%

Условия реакции

Обработка

1. 1
   Другоеto react in the same manner

Методика

Compound 22 (0.3 g, 0.80 mmol) was allowed to react in the same manner as described in the preparation of compound 40 to give 43. White solid; yield: 61.3%; mp 277-279° C.; MS (EI, 70 eV): m/z 285 (M+); IR (KBr): 1622.13 (C═O) cm−1; 1H-NMR (DMSO-d6 200 MHz): δ 3.82 (s, 3H), 6.04 (s, 1H), 7.01 (s, 1H), 7.32-7.50 (m, 3H), 7.50-7.67 (m, 2H), 10.22 (s, 1H), 11.68 (s, 1H); 13C-NMR (DMSO-d6, 50 MHz): δ 55.52, 102.72, 105.37, 108.20, 116.28 (d, J=22.5 Hz), 118.07, 122.94, 124.92, 130.75, 131.99 (d, J=7.95 Hz), 136.45, 143.61, 146.58, 151.59, 158.98 (d, J=246.9 Hz), 175.30; Anal. calcd for C16H12FNO3: C, 67.36; H, 4.24; N, 4.91. Found: C, 67.37; H, 4.26; N, 4.90.

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