Реакция #58559

Уравнение реакции

product

6-Benzyl-4,5,6,7,7a, 8-hexahydro-3bH-3-thia-6-aza-cyclopenta[α]indene

K2CO3

Ace-Cl

→

subtitle compound

Выход 94.0%

4,5,6,7,7a,8-Hexahydro-3bH-3-thia-6-aza-cyclopenta[α]indene

Выход 94.0%

Растворители

dichloroethane

Условия реакции

Обработка

1. 1
   ФильтрацияNext, the reaction mixture was filtered
2. 2
   Концентрированиеconcentrated
3. 3
   workup.DISSOLUTIONthe residue was dissolved in anhydrous MeOH (25 ml)
4. 4
   КонцентрированиеThe MeOH was concentrated
5. 5
   Другоеtriturated with ether

Методика

The product of step f) (1.16 g, 4.3 mmol) in dichloroethane (21 ml) was treated with K2CO3 (2.38 g, 17.2 mmol) and Ace-Cl (1.86 ml, 17.2 mmol) at 800C for 16 hours. Next, the reaction mixture was filtered, concentrated and the residue was dissolved in anhydrous MeOH (25 ml) and stirred for 1 hour at 22° C. The MeOH was concentrated and triturated with ether to give 874 mg (94%) of the subtitle compound. MS calculated for C10H13NS+H 180, observed 180.

Источник