Реакция #58551

Уравнение реакции

product

5-Benzyl-4,5,6,7,7a,8-hexahydro-3bH-1-thia-5-aza-cyclopenta[α]indene

K2CO3

Ace-Cl

→

subtitle compound

Выход 61.0%

4,5,6,7,7a,8-Hexahydro-3bH-1-thia-5-aza-cyclopenta[α]indene

Выход 61.0%

Растворители

dichloroethane

Условия реакции

Обработка

1. 1
   ФильтрацияNext, the reaction mixture was filtered
2. 2
   Концентрированиеconcentrated
3. 3
   workup.DISSOLUTIONthe residue was dissolved in anhydrous MeOH (25 ml)
4. 4
   КонцентрированиеThe MeOH was concentrated
5. 5
   Другоеtriturated with ether

Методика

The product from step g) (963 mg, 3.58 mmol) in dichloroethane (18 ml) was treated with K2CO3 (1.97 g, 14.3 mmol) and Ace-Cl (1.54 ml, 14.3 mmol) at 80° C. for 16 hours. Next, the reaction mixture was filtered, concentrated and the residue was dissolved in anhydrous MeOH (25 ml) and stirred for 1 h at 22° C. The MeOH was concentrated and triturated with ether to give 467 mg (61%) of the subtitle compound. MS calculated for C10H13NS+H 180, observed 180.

Источник