Реакция #417953

Уравнение реакции

4′-Azido-2′-fluoro-N2-(4-methoxytrityl)-2′-deoxyguanosine

→

( 27 )

Выход 61.3%

4′-azido-2′-deoxy-2′-fluoroguanosine

Выход 61.3%

Растворители

HCOOH

Условия реакции

Обработка

1. 1
   ДругоеThe solvent was evaporated at R.T. and co-evaporated with MeOH/toluene (3 times)
2. 2
   ДругоеPurification

Методика

Compound (27)—A solution of compound 50-8 (580 mg, 0.72 mmol) in 7N NH3 in CH3OH (30 mL) was stirred at R.T. overnight. The solvent was evaporated in vacuo, and the residue was purified on silica gel column using DCM/MeOH (95:5 to 90:10) to give 4′-azido-2′-fluoro-N2-(4-methoxytrityl)-2′-deoxyguanosine (332 mg, 77%). 4′-Azido-2′-fluoro-N2-(4-methoxytrityl)-2′-deoxyguanosine (80 mg, 0.13 mmol) was dissolved in 80% HCOOH (3 mL), stirred at R.T. for 3 hours. The solvent was evaporated at R.T. and co-evaporated with MeOH/toluene (3 times). Purification using RP-HPLC (water:acetonitrile) gave (27) (26.0 mg, 61%) as a white foam after lyophilization. 1H NMR (DMSO-d6) δ 3.55-3.67 (m, 2H), 4.69-4.77 (m, 1H), 5.37 (dd, J=2.4, 4.8 Hz, 1H), 5.51 (t, J=2.8 Hz, 1H), 5.65 (t, J=6.0 Hz, 1H), 6.13 (d, J=7.6 Hz, 1H), 6.30 (dd, J=2.4, 18.4 Hz, 1H), 6.60 (br s, 1H), 7.91 (s, 1H), 10.74 (br s, 1H); 19F NMR δ (−199.0 to −199.25, m); ESI-LCMS m/z=325.3 [M+H]+.

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