Реакция #417918

Уравнение реакции

lithium aluminum hydride

15

methyl 3-(undec-4Z-enyloxy)benzoate

→

colorless oil

Выход 99.9%

3-(undec-4Z-enyloxy)benzyl alcohol

Выход 99.9%

Растворители

ether

ether

Условия реакции

Обработка

1. 1
   ДругоеAfter reaction for 1 hour 30 minutes
2. 2
   ФильтрацияAfter filtering through Celite
3. 3
   Сушкаdrying over Na2SO4
4. 4
   Концентрированиеconcentrating

Методика

35 mg of lithium aluminum hydride (922 μmol) are added, at 0° C., to 140 mg of 15 (460 μmol) in ether (3 mL). After reaction for 1 hour 30 minutes, the reaction medium is diluted with ether and hydrolyzed with two drops of water. After filtering through Celite, drying over Na2SO4 and concentrating, 127 mg of a colorless oil are isolated, i.e. a yield of 99%.

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