Реакция #41281

Уравнение реакции

Bromoethane

compound 14a

3-[(Anthracen-9-ylmethyl)-amino]-propan-1-ol

K2CO3

→

14b

Выход 82.0%

3-(Anthracen-9-ylmethyl-ethyl-amino)-propan-1-ol

Выход 82.0%

Растворители

acetonitrile

Условия реакции

Обработка

1. 1
   КонцентрированиеAfter confirmation of the disappearance of 14a by TLC, the solution was concentrated under reduced pressure
2. 2
   workup.DISSOLUTIONThe residue was dissolved in CH2Cl2 (20 mL)
3. 3
   Промывкаwashed three times with aqueous sodium carbonate
4. 4
   ДругоеThe organic layer was separated
5. 5
   Сушкаdried with anhydrous Na2SO4
6. 6
   Фильтрацияfiltered
7. 7
   Концентрированиеconcentrated under vacuum

Методика

Bromoethane (616 mg, 5.65 mmol) was dissolved in anhydrous acetonitrile and was added to the stirring mixture of compound 14a (500 mg, 1.9 mmol) and anhydrous K2CO3 (781 mg, 5.7 mmol). The mixture was then stirred overnight at 75° C. under a N2 atmosphere. After confirmation of the disappearance of 14a by TLC, the solution was concentrated under reduced pressure. The residue was dissolved in CH2Cl2 (20 mL) and washed three times with aqueous sodium carbonate. The organic layer was separated, dried with anhydrous Na2SO4, filtered and concentrated under vacuum. Flash column chromatography of the residue gave 14b as a light yellow oil. Yield 82%; Rf=0.35 (3% MeOH/CHCl3); 1H NMR (CDCl3) δ 8.28 (m, 3H), 7.86 (d, 2H), 7.44 (m, 2H), 7.36 (m, 2H), 4.29 (s, 2H), 3.15 (t, 2H), 2.65 (q, 2H), 2.52 (t, 2H), 1.43 (q, 2H), 1.16 (t, 3H); 13C NMR (CDCl3) δ 131.2, 131.1, 129.3, 129.0, 127.6, 125.8, 124.8, 124.4, 63.4, 52.6, 50.5, 47.7, 28.1, 11.6. HRMS (FAB) m/z calcd. for C20H23NO (M+H)+ 294.1852; found 294.1859.

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