Реакция #354447

ord-aa2f25c9885f4ab990d69abcfb05d88f

Уравнение реакции

Cl
hydrogen chloride
CCCCCCCCCCCCCCCCCCO
stearyl alcohol
COC(=O)CC#N
methyl cyano acetate
CCCCCCCCCCCCCCCCCCOC(=N)CC(=O)OC.Cl
stearyl methoxycarbonylacetimidate hydrochloride
Выход 46.8%

Реагенты

Нет

Растворители

Условия реакции

Подробные условия
See reaction.notes.procedure_details.

Обработка

  1. 1
    ДругоеThe resulting white precipitates
  2. 2
    Промывкаwere washed with ethylether
  3. 3
    Другоеdried

Методика

In a mixture of 27.0 parts of stearyl alcohol in 200 volume parts of dry ethyl ether and 9.9 parts of methyl cyano acetate was introduced about 5.3 parts of dry hydrogen chloride gas at room temperature, followed by keeping at room temperature for 2 days. The resulting white precipitates were washed with ethylether and dried to give 19.0 parts of stearyl methoxycarbonylacetimidate hydrochloride melting at 83° to 85°C (decomposition). Yield: 46.8%

Источник

DOI: 10.6084/m9.figshare.5104873.v1Патент: US03941823uspto-grants-1976_03