Реакция #316039

ord-17d9e8d3d39149adb82d258abf303c73

Уравнение реакции

Cl
hydrochloric acid
[Na+].[OH-]
Sodium hydroxide
O
water
O=C1Nc2ccc(F)cc2C1=O
5-Fluoro-1H-indole-2,3-dione
O=C(CO)c1ccccc1
2-hydroxy-1-phenyl-ethanone
O=C(O)c1c(O)c(-c2ccccc2)nc2ccc(F)cc12
6-fluoro-3-hydroxy-2-phenyl-quinoline-4-carboxylic acid
Выход 21.0%

Растворители

Условия реакции

Подробные условия
See reaction.notes.procedure_details.

Обработка

  1. 1
    Другоеto prepare a solution
  2. 2
    Промывкаthe precipitated crystal was washed with methanol and water

Методика

5-Fluoro-1H-indole-2,3-dione (1.19 g) and 2-hydroxy-1-phenyl-ethanone (2.25 g) were dissolved in methanol (70 ml) to prepare a solution. Sodium hydroxide (4.82 g) and water (30 ml) were added to the solution, and the mixture was stirred at room temperature overnight. Dilute hydrochloric acid was added to the reaction solution, and the precipitated crystal was washed with methanol and water to give 6-fluoro-3-hydroxy-2-phenyl-quinoline-4-carboxylic acid (427 mg, yield 21%).

Источник

DOI: 10.6084/m9.figshare.5104873.v1Патент: US07560558B2uspto-grants-2009_07