Реакция #2288611

Уравнение реакции

mixture

4-(4-chloro-3-fluoro-6-methoxyquinolin-2-yl)benzoic acid

→

4-(3-fluoro-6-methoxyquinolin-2-yl)benzoic acid

Выход 66.0%

Растворители

MeOH

Условия реакции

Обработка

1. 1
   ФильтрацияThe solids were filtered off
2. 2
   Концентрированиеthe filtrate was concentrated
3. 3
   Другоеto give the product (60 mg, two-step yield 66%)

Методика

To a solution of the mixture from Step 1 in absolute MeOH (5 mL) was added Pd/C (10% Pd, 100 mg). The mixture was stirred at 25° C. for 1 hour under H2 atmosphere. The solids were filtered off and the filtrate was concentrated to give the product (60 mg, two-step yield 66%).

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