Реакция #2186189

ord-629e7faa6b9b41eba5bf992ec17d492c

Уравнение реакции

O=C(CBr)c1ccccc1
phenacyl bromide
C1CCSC1
tetrahydrothiophene
O
water
CCOCC
diethyl ether
O=C(C[S+]1CCCC1)c1ccccc1.[Br-]
Phenacyltetrahydrothiophenium Bromide

Реагенты

Нет

Растворители

Условия реакции

Подробные условия
See reaction.notes.procedure_details.

Обработка

  1. 1
    Другоеseparated into two layers

Методика

88.2 g (0.44 mole) of phenacyl bromide and 39.1 g (0.44 mole) of tetrahydrothiophene were dissolved in 220 g of nitromethane, which was stirred for 4 hours at room temperature. 800 g of water and 400 g of diethyl ether were added to the reaction solution whereupon the mixture separated into two layers. The aqueous layer was taken out, which was an aqueous solution of the target compound, phenacyltetrahydrothiophenium bromide.

Источник

DOI: 10.6084/m9.figshare.5104873.v1Патент: US07569324B2uspto-grants-2009_08