Реакция #2161235

ord-fdaecefed0aa4e6d9b252e9da8e71d29

Уравнение реакции

O=C(CBr)c1ccccc1
phenacyl bromide
C1CCSC1
tetrahydrothiophene
O
water
CCOCC
diethyl ether
O=C(C[S+]1CCCC1)c1ccccc1.[Br-]
Phenacyltetrahydrothiophenium Bromide

Реагенты

Нет

Растворители

Условия реакции

Подробные условия
See reaction.notes.procedure_details.

Обработка

  1. 1
    Другоеseparated into two layers

Методика

88.2 g (0.44 mole) of phenacyl bromide and 39.1 g (0.44 mole) of tetrahydrothiophene were dissolved in 220 g of nitromethane, which was stirred for 4 hours at room temperature. 800 g of water and 400 g of diethyl ether were added to the reaction solution whereupon the mixture separated into two layers. The aqueous layer was taken out, which was an aqueous solution of the target compound, phenacyltetrahydrothiophenium bromide.

Источник

DOI: 10.6084/m9.figshare.5104873.v1Патент: US07919226B2uspto-grants-2011_04