Реакция #215065

ord-f7e0246b35f34639a9a6b4913a020fc3

Уравнение реакции

O=S(=O)([O-])[O-]
sulfate
O=P([O-])([O-])[O-].O=P([O-])([O-])[O-].O=P([O-])([O-])[O-].[Ca+2].[Ca+2].[Ca+2].[Ca+2].[Ca+2].[F-]
phosphate rock
[Ca]
calcium
O=S(=O)(O)O
Sulfuric acid
O=S(=O)([O-])[O-]
sulfate
O=S(=O)([O-])[O-]
sulfate
→
O.O=S(=O)([O-])[O-].O=S(=O)([O-])[O-].[Ca+2].[Ca+2]
calcium sulfate hemihydrate

Реактанты

O=S(=O)([O-])[O-]
sulfate
O=P([O-])([O-])[O-].O=P([O-])([O-])[O-].O=P([O-])([O-])[O-].[Ca+2].[Ca+2].[Ca+2].[Ca+2].[Ca+2].[F-]
phosphate rock
[Ca]
calcium
O=S(=O)(O)O
Sulfuric acid
O=S(=O)([O-])[O-]
sulfate
O=S(=O)([O-])[O-]
sulfate

Реагенты

Нет

Условия реакции

Подробные условия
See reaction.notes.procedure_details.

Методика

Sulfuric acid is added in amounts such that the sulfate content of the added acid and the sulfate content of the added rock is equivalent to about 90% to about 100% (more preferred 93-99.5%) of the stoichiometric amount of sulfate required to react with calcium added in the phosphate rock to form calcium sulfate hemihydrate.

Источник

DOI: 10.6084/m9.figshare.5104873.v1Патент: US04258008uspto-grants-1981_03