Реакция #2045039

ord-186d23c21cfc453899c658163c897378

Уравнение реакции

COC(=O)CCCCCOc1ccc([N+](=O)[O-])cc1
6-(4-nitrophenoxy) hexanoic acid methyl ester
COC(=O)CCCCCOc1ccc([N+](=O)[O-])cc1
6-(4-Nitro-phenoxy)-hexanoic acid methyl ester
O=C(O)CCCCCOc1ccc([N+](=O)[O-])cc1
53
Выход 80.2%
O=C(O)CCCCCOc1ccc([N+](=O)[O-])cc1
6-(4-Nitrophenoxy)-hexanoic acid
Выход 80.2%

Растворители

Условия реакции

Подробные условия
See reaction.notes.procedure_details.

Обработка

  1. 1
    Температураwas refluxed for 16 hours
  2. 2
    Фильтрацияfiltered
  3. 3
    Другоеdried
  4. 4
    Другоеrecrystallised from a mixture of ethyl acetate:hexane (1:6)

Методика

A mixture of 6-(4-nitrophenoxy) hexanoic acid methyl ester 39 (125 g, 468.16 mmol) and concentrated HCl (1250 ml) was refluxed for 16 hours. The reaction mixture was cooled to room temperature, filtered, dried and recrystallised from a mixture of ethyl acetate:hexane (1:6) to get pure 53 (95 g, 80.2%) as a white powder. M.p: 104-107° C.

Источник

DOI: 10.6084/m9.figshare.5104873.v1Патент: US08409559B2uspto-grants-2013_04