Реакция #1951031

Уравнение реакции

2,5,6-Trichloro-3-acetyl-1-(5-O-acetyl-β-D-ribofuranosyl)indole

sodium methoxide

→

4.46

Выход 81.3%

2,5,6-Trichloro-3-acetyl-1-(β-D-ribofuranosyl)indole

Выход 81.3%

Растворители

MeOH

Условия реакции

Обработка

1. 1
   Другоеthe solvent was then removed under vacuum
2. 2
   Экстракцияthe suspension extracted with EtOAc (2×50 mL)
3. 3
   СушкаThe combined organic extracts were dried over MgSO4
4. 4
   Фильтрацияfiltered
5. 5
   Другоеevaporated
6. 6
   Другоеto yield a white solid
7. 7
   ДругоеThe solid was recrystallized

Методика

2,5,6-Trichloro-3-acetyl-1-(5-O-acetyl-β-D-ribofuranosyl)indole (4.43, 232 mg, 0.53 mmol) was dissolved in dry MeOH (20 mL) to which was added sodium methoxide (35 mg, 0.65 mmol). The solution was stirred at room temperature for 45 min, and the solvent was then removed under vacuum. The residue was suspended in 10% aqueous NaHCO3 (50 mL) and the suspension extracted with EtOAc (2×50 mL). The combined organic extracts were dried over MgSO4, filtered and evaporated to yield a white solid. The solid was recrystallized from boiling EtOAc/hexane to yield 170 mg (81%) of 4.46 as a white crystalline solid: mp 249-250 C; Rf0.4 (10% MeOH/CHCl3); 1H-NMR (500 MHz, DMSO-d6): δ 8.63 (s, 1H), 8.41 (s, 1H), 6.07 (d, 1H), 5.45-5.42 (m, 2H, D2O exch.), 5.30 (d, 1H, D2O exch.), 4.44 (q, 1H), 4.17 (d, 1H), 4.03 (d, 1H), 3.75 (b, 2H), 2.63 (s, 3H). 13C-NMR (125 MHz, DMSO-d6): δ 192.17, 133.10, 132.38, 126.21, 126.00, 125.73, 122.00, 115.44, 112.99, 88.97, 86.39, 71.63, 69.54, 60.97, 30.72. HRMS (ES) m/z calcd. for C15H14C13NO5□Na 415.9835, found 415.9843. Anal calcd for C15H14Cl3NO5: C, 45.65; H, 3.58; N, 3.55. Found: C, 45.75; H, 3.78; N, 3.61.

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