Реакция #1886838

Уравнение реакции

8-bromo-1-octanol

2-(8-bromo-octyloxy)-tetrahydro-pyran

2-phenoxyethanol

→

2-(8-(2-phenoxy-ethoxy)-octyloxy)-tetrahydro-pyran

Условия реакции

Методика

The title compound, m/e=407.6 ([M−H]−), was produced in analogy with example 54, steps 1 to 6. Thus, 8-bromo-1-octanol was protected in step 1, leading to 2-(8-bromo-octyloxy)-tetrahydro-pyran, which was reacted in step 2 with 2-phenoxyethanol, affording 2-(8-(2-phenoxy-ethoxy)-octyloxy)-tetrahydro-pyran, which after deprotection in step 3 gave 8-(2-phenoxy-ethoxy)-octan-1-ol. This was oxidized in step 4 to 8-(2-phenoxy-ethoxy)-octanoic acid, which was coupled in step 5 with (R)-3-amino-4-dimethylamino-butyric acid benzyl ester dihydrochloride, leading to (R)-4-dimethylamino-3-[8-(2-phenoxy-ethoxy)-octanoylamino]-butyric acid benzyl ester, which was hydrogenated in step 6.

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