Реакция #1869153

Уравнение реакции

HCl

ethyl 3,3-ethylenedioxydodecanoate

LiOH.H2O

THF

→

3,3-ethylenedioxydodecanoic acid

Выход 81.0%

Растворители

water

Условия реакции

Обработка

1. 1
   Экстракцияextracted with ethyl acetate (3×50 mL)
2. 2
   Промывкаwashed once with brine
3. 3
   СушкаThe organic phase was dried (MgSO4)
4. 4
   Концентрированиеconcentrated

Методика

To a 25 mL flask were added ethyl 3,3-ethylenedioxydodecanoate (1.131 g, 3.95 mmol), LiOH.H2O (840 mg, 20 mmol), THF (5 mL), and water (5 mL). The mixture was stirred at room temperature overnight. The solution was acidified by the addition of 1 M HCl (50 mL), and extracted with ethyl acetate (3×50 mL). The organic layers were combined and washed once with brine. The organic phase was dried (MgSO4) and concentrated to give 3,3-ethylenedioxydodecanoic acid (0.824 g, 3.19 mmol) in 81% yield. 1H NMR (500 MHz, CDCl3) δ 0.88 (t, J=7 Hz, 3H), 1.20-1.44 (m, 14H), 1.72-1.80 (m, 2H), 2.72 (s, 2H), 3.98-4.10 (m, 4H); 13C NMR (125 MHz, CDCl3) δ 13.9, 22.5, 23.3, 29.13, 29.35, 29.39, 29.50, 31.7, 37.5, 42.2, 64.9 (2 C), 109.2, 174.8.

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