Реакция #1869149

Уравнение реакции

10-undecenoic acid

(COCl)2

→

10-undecenoyl chloride

Выход 100.0%

Растворители

CH2Cl2

Условия реакции

Обработка

1. 1
   ДругоеThe solvent was removed under reduced pressure

Методика

To a stirred solution of 10-undecenoic acid (5.055 mL, 25 mmol) in CH2Cl2 (50 mL) was slowly added (COCl)2 (4.364 mL, 50 mmol). The mixture was stirred at room temperature overnight. The solvent was removed under reduced pressure to give 10-undecenoyl chloride (25 mmol). The product was used for the next reaction without further purification. 1H NMR (500 MHz, CDCl3) δ 1.29-1.48 (m, 10H), 1.71 (m, 2H), 2.05 (m, 2H), 2.88 (t, J=7 Hz, 2H), 4.98 (m, 2H), 5.80 (m, 1H).

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