Реакция #170968
ord-d6672ac9b2414dc78a3e6a392bd4b291
Уравнение реакции
methyl 6-bromohexanoate
paracetamol
K2CO3
sodium iodide
→
15
6-(4-Acetylaminophenoxy)-hexanoic acid methyl ester
Реагенты
Нет
Растворители
Условия реакции
Подробные условия
See reaction.notes.procedure_details.
Обработка
- 1Температураrefluxed for 60 hours
- 2workup.DISTILLATIONAcetone was distilled off
- 3workup.ADDITIONwater (3 L) was added
- 4ФильтрацияCrude 15 was filtered
- 5Другоеdried
- 6Другоеrecrystallised from a mixture of chloroform:hexane (1:5)
Методика
To a mixture of paracetamol (250 gm, 1.654 mmol), anhydrous K2CO3 (800 gm, 5.789 mmol) and sodium iodide (17 g, 113 mmol) in anhydrous acetone (5 L) was added methyl 6-bromohexanoate (470 g, 2.25 mmol) and refluxed for 60 hours. Acetone was distilled off and water (3 L) was added. Crude 15 was filtered, dried and recrystallised from a mixture of chloroform:hexane (1:5) to give pure 15 (195 g, 66%) as a white powder with an m.p between 96.4-98.8° C.