Реакция #11149

Уравнение реакции

HCl

methanol

2-[2-(2-Chloro-6-methoxyphenyl)ethenyl]-5-methoxy-1H-indole

5-Methoxy-2-[2-(3,5-dinitrophenyl)ethenyl]-1H-indole

2-bromoethyl tetrahydro-2H-pyran-2-yl ether

→

2-{2-[2-(2-Chloro-6-methoxyphenyl)ethenyl]-5-methoxy-1H-indol-1-yl}ethanol

Выход 91.0%

Условия реакции

Обработка

1. 1
   Другоеprepared

Методика

The reaction of 2-[2-(2-Chloro-6-methoxyphenyl)ethenyl]-5-methoxy-1H-indole (II; Ar=2-chloro-6-methoxyphenyl) (102) prepared as described in example 55 with 2-bromoethyl tetrahydro-2H-pyran-2-yl ether using the procedure described in example 38 followed by reaction of the crude product with 2N HCl in methanol gave 2-{2-[2-(2-Chloro-6-methoxyphenyl)ethenyl]-5-methoxy-1H-indol-1-yl}ethanol (III; Ar=2-chloro-6-methoxyphenyl, R10═CH2CH2OH) (109) in a 91% yield as a mixture of E/Z isomers, which was used without further purification.

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