Реакция #1106641

Уравнение реакции

H2O

1-(2-hydroxy-4-(methoxymethoxy)phenyl)ethanone

6-methoxy-3-pyridine-carboxaldehyde

KOH

EtOH

→

chalcone

Выход 34.0%

Условия реакции

Методика

4.18 g (21.3 mmol) of 1-(2-hydroxy-4-(methoxymethoxy)phenyl)ethanone, 2.8 g of 6-methoxy-3-pyridine-carboxaldehyde (20.4 mmol), and 1.8 g (32.1 mmol) of KOH were reacted in 60 ml of EtOH and 20 ml of H2O ml to give 2.18 g (34%) of chalcone after purification. 1H NMR (300 MHz, CDCl3): δ 13.27 (s, 1H), 8.42 (d, J=2.4 Hz, 1H), 7.95-7.82 (m, 3H), 7.50 (d, J=15.6 Hz, 1H), 6.83 (d: J=8.7 Hz, 1H), 6.67 (d, J=2.7 Hz; 1H), 6.61 (d, d, J=2.4, 9.0 Hz, 1H), 5.25 (s, 2H), 4.02 (s, 3H), 3.51 (s, 3H).

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