반응 #72455

반응 방정식

AlCl3

NaCl

aluminum chloride

hydrochloric acid

3-chloropropanoyl chloride

1,2,3,4-tetrahydroquinoline

HCl

→

1,2,6,7-tetrahydro-5H-pyrido[3,2,1-ij]quinolin-3-one

수율 88.0%

용매

water

acetone

acetone

반응 조건

후처리

1. 1
   온도the mixture was refluxed for 1 h
2. 2
   workup.ADDITIONwas poured into 500 ml
3. 3
   추출extracted with ethyl acetate (3×150 ml)
4. 4
   세척After washing with 1N HCl and brine
5. 5
   건조drying over MgSO4 the solvent
6. 6
   기타was removed under reduced pressure
7. 7
   기타the crude product was obtained as a pale yellow solid
8. 8
   온도On cooling
9. 9
   추출Extraction with ethyl acetate (3×200 ml)
10. 10
    건조by drying over MgSO4 and removal of the solvent

실험 절차

A solution of 3-chloropropanoyl chloride (9.1 ml, 95.0 mmol) in 20 ml dry acetone was added dropwise to a solution of 1,2,3,4-tetrahydroquinoline (26.6 g, 0.20 mol) in 80 ml dry acetone and the mixture was refluxed for 1 h. After cooling to ambient temperature the solution was poured into 500 ml stirred 2N HCl and extracted with ethyl acetate (3×150 ml). After washing with 1N HCl and brine and drying over MgSO4 the solvent was removed under reduced pressure and the crude product was obtained as a pale yellow solid. This was added portionwise to a molten mixture of AlCl3 (60.0 g, 0.45 mol) and NaCl (17.5 g, 300 mmol) at 150° C. and stirred for additional 30 minutes. On cooling, excess aluminum chloride was decomposed by the addition of a chilled mixture of 20 ml concentrated hydrochloric acid and 500 ml water. Extraction with ethyl acetate (3×200 ml), followed by drying over MgSO4 and removal of the solvent gave 1,2,6,7-tetrahydro-5H-pyrido[3,2,1-ij]quinolin-3-one (15.6 g, 83.3 mmol, 88%) as a yellow solid.

출처