반응 #55347

ord-b78871df4f474f2d87a824bd1261030c

반응 방정식

O=S(=O)([O-])[O-]
sulfate
O=P([O-])([O-])[O-].O=P([O-])([O-])[O-].O=P([O-])([O-])[O-].[Ca+2].[Ca+2].[Ca+2].[Ca+2].[Ca+2].[F-]
phosphate rock
[Ca]
calcium
O=S(=O)(O)O
Sulfuric acid
O=S(=O)([O-])[O-]
sulfate
O=S(=O)([O-])[O-]
sulfate
→
O.O=S(=O)([O-])[O-].O=S(=O)([O-])[O-].[Ca+2].[Ca+2]
calcium sulfate hemihydrate

반응물

O=S(=O)([O-])[O-]
sulfate
O=P([O-])([O-])[O-].O=P([O-])([O-])[O-].O=P([O-])([O-])[O-].[Ca+2].[Ca+2].[Ca+2].[Ca+2].[Ca+2].[F-]
phosphate rock
[Ca]
calcium
O=S(=O)(O)O
Sulfuric acid
O=S(=O)([O-])[O-]
sulfate
O=S(=O)([O-])[O-]
sulfate

시약

없음

반응 조건

상세 조건
See reaction.notes.procedure_details.

실험 절차

Sulfuric acid is added in amounts such that the sulfate content of the added acid and the sulfate content of the added rock is equivalent to about 90% to about 100% (more preferred 93-99.5%) of the stoichiometric amount of sulfate required to react with calcium added in the phosphate rock to form calcium sulfate hemihydrate.

출처

DOI: 10.6084/m9.figshare.5104873.v1특허: US04220630uspto-grants-1980_09