반응 #50915

반응 방정식

crude product 403

tert-Butyl 2-(3-cyanophenyl)-3-propyl-3-(2,2,2-trifluoracetyl)carbazate

water

lithium hydroxide

→

404

수율 63.8%

tert-Butyl 2-(3-cyanophenyl)-3-propylcarbazate

수율 63.8%

용매

methanol

반응 조건

실험 절차

5.64 g (15.187 mmol) of crude product 403 are dissolved in 100 ml of methanol and treated at RT with 10 ml of completely deionized water and 1.08 g (45.24 mmol) of lithium hydroxide. The reaction mixture is then stirred for 5 h. After customary work-up, 2.67 g (63.8%) of 404 are thus obtained as an oil; MS(FAB)=276.

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