반응 #302860

반응 방정식

sodium hydroxide

compound 24

6-methoxy-4′-aminoflavone

Sodium cyanoborohydride

paraformaldehyde

→

compound 25

6-methoxy-4′-dimethylaminoflavone

용매

acetic acid

반응 조건

후처리

1. 1
   workup.STIRRINGThe obtained mixture was stirred at room temperature for 3 hours
2. 2
   workup.ADDITIONwas added to the reaction solution
3. 3
   추출the obtained mixture was then extracted with 50 ml (25 ml×2) of chloroform
4. 4
   건조The extract was dried over anhydrous sodium sulfate
5. 5
   workup.DISTILLATIONthe solvent was then distilled away under reduced pressure

실험 절차

Sodium cyanoborohydride (891 mg, 14.1 mmol) was slowly added to an acetic acid solution (30 ml) that contained compound 24 (630 mg, 2.36 mmol) and paraformaldehyde (707 mg, 23.6 mmol), while stirring. The obtained mixture was stirred at room temperature for 3 hours. After completion of the reaction, 50 ml of a 1 N sodium hydroxide aqueous solution was added to the reaction solution, and the obtained mixture was then extracted with 50 ml (25 ml×2) of chloroform. The extract was dried over anhydrous sodium sulfate, and the solvent was then distilled away under reduced pressure, so as to obtain a product of interest, 6-methoxy-4′-dimethylaminoflavone (compound 25) in the form of a yellow crystal. Yield: 450 mg (yield constant: 64.6%) 1H NMR (300 MHz, CDCl3) δ8.31 (s, 1H), 7.69-7.75 (m, 3H), 7.39 (d, J=8.7 Hz, 1H), 6.62-6.66 (m, 3H), 4.18 (s, 1H). 2.91 (s, 3H).

출처