반응 #1772015

반응 방정식

2

Methyl Cyclopentylmandelate

N-methyl-3-pyrrolidinol

EtOAc

EtOH

→

product 4

수율 72.0%

N-Methyl-3-pyrrolidinyl cyclopentylmandelate

수율 72.0%

용매

n-heptane

heptane

반응 조건

후처리

1. 1
   workup.DISTILLATIONhad been distilled
2. 2
   workup.ADDITIONAbout 0.003 g of sodium was added
3. 3
   온도heated for 2 h as the distillation
4. 4
   workup.ADDITIONMore heptane was added at such a rate as
5. 5
   workup.ADDITIONAdditional sodium was added at the end of an hour
6. 6
   온도The solution was then cooled
7. 7
   추출extracted with 3N HCl
8. 8
   추출The acid extract
9. 9
   추출extracted three times with ether
10. 10
    기타Removal of the dried ether solution
11. 11
    기타gave a crude oil

실험 절차

A solution of 2 (2.20 g, 9.4 mmol) and N-methyl-3-pyrrolidinol (3, 1.30 g, 13 mmol) in 40 ml of n-heptane was heated until 20 ml of heptane had been distilled. About 0.003 g of sodium was added, and the solution was stirred and heated for 2 h as the distillation was continued. More heptane was added at such a rate as to keep the reaction volume constant. Additional sodium was added at the end of an hour. The solution was then cooled and extracted with 3N HCl. The acid extract was made alkaline with concentrated NaOH and extracted three times with ether. Removal of the dried ether solution gave a crude oil. Flash chromatography of the crude product on silica gel with 8:1 EtOAc:EtOH gave pure product 4 (2.053 g, 72%). Analysis for C18H25NO3. Calcd: C, 71.26; H, 8.31; N, 4.62. Found: C, 71.55; H, 8.44; N, 4.68. 1H NMR (CDCl3, 500 MHz): 1.27-1.35, 1.40-1.47, 1.54-1.60, 1.75-1.90 [8H, m, (CH2)4], 2.12-2.30, 2.52-2.57, 2.64-2.81 (6H, m CH2NCH2CH2), 2.33, 2.36 (3H, 2s, NCH3), 2.93 [(1H, p, CHC(OH)], 3.83 (1H, bs, OH), 5.23 (1H, m, CO2CH), 7.23-7.36, 7.64-7.67 (5H, m, Ph) ppm.

출처