반응 #1702094
ord-8cd9e3c53e524f6ca27a6afb6d161606
반응 방정식
(2-Benzyloxycarbonylamino-ethyl)-methyl-phosphinic acid ethyl ester
EtOH
→
(2-amino-ethyl)-methyl-phosphinic acid ethyl ester
수율 90.0%
용매
반응 조건
상세 조건
See reaction.notes.procedure_details.
후처리
- 1기타was run at room temperature
- 2여과The reaction was then filtered through Supercell NF
- 3농축the filtrate was concentrated
실험 절차
(2-Benzyloxycarbonylamino-ethyl)-methyl-phosphinic acid ethyl ester (1.3 g, 4.56 mmol) and 10% Pd/C (485 mg) were combined in a flask and EtOH (46 mL) was added. The reaction flask atmosphere was exchanged for H2 and the reaction was run at room temperature until complete, as determined by TLC (eluent: 100% EtOAc). The reaction was then filtered through Supercell NF and the filtrate was concentrated to yield (2-amino-ethyl)-methyl-phosphinic acid ethyl ester (615 mg, 90%) as a yellow oil in which white crystals began to form under high vacuum.