반응 #166247

반응 방정식

4-(2-fluoro-4-methylsulfanyl-phenylamino)-1H-indazole-5-carboxylic acid (2-vinyloxy-ethoxy)-amide

hydrochloric acid

→

solid

수율 55.0%

4-(2-Fluoro-4-methylsulfanyl-phenylamino)-1H-indazole-5-carboxylic acid (2-hydroxy-ethoxy)-amide

수율 55.0%

용매

methanol

반응 조건

후처리

1. 1
   농축The reaction mixture was then concentrated in vacuo
2. 2
   workup.DISSOLUTIONthe residue dissolved in methanol and to this solution
3. 3
   workup.ADDITIONwas added water causing a precipitate
4. 4
   기타to form which
5. 5
   여과was filtered off
6. 6
   추출The filtrate was extracted twice with ethyl acetate
7. 7
   건조the combined extracts dried (Na2SO4)
8. 8
   여과filtered
9. 9
   농축concentrated in vacuo
10. 10
    기타to give a solid
11. 11
    기타The solid was triturated in diethyl ether

실험 절차

A solution of 4-(2-fluoro-4-methylsulfanyl-phenylamino)-1H-indazole-5-carboxylic acid (2-vinyloxy-ethoxy)-amide (45 mg, 0.112 mmol) in methanol (5 mL) was treated with hydrochloric acid (1M, 0.225 mL, 0.22 mmol) and the reaction mixture stirred at room temperature for 2 hours. The reaction mixture was then concentrated in vacuo and the residue dissolved in methanol and to this solution was added water causing a precipitate to form which was filtered off. The filtrate was extracted twice with ethyl acetate, the combined extracts dried (Na2SO4), filtered and concentrated in vacuo. The crude product was combined with the earlier solid precipitate and subjected to flash chromatography (Si—PPC, gradient 0 to 10% methanol in DCM) to give a solid. The solid was triturated in diethyl ether to give a pale tan solid (23 mg, 55%). LCMS (Method A) RT 7.79 [M+H]+ 377. 1H NMR (MeOD, 400 MHz): 7.52-7.44 (1 H, m), 7.21-7.09 (3 H, m), 7.06 (1 H, dd, J=8.41, 2.08 Hz), 6.93 (1 H, d, J=8.88 Hz), 4.54 (1 H, s), 4.02-3.98 (2 H, m), 3.75 (2 H, dd, J=5.28, 4.05 Hz), 2.48 (3 H, s).

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