반응 #1446308

반응 방정식

NaOH

NAD+

phosphate

sodium iodide

→

NADH

수율 19.5%

반응 조건

후처리

1. 1
   기타The Fisher-Porter bottle was evacuated
2. 2
   workup.ADDITIONrefilled with argon three times
3. 3
   기타The Fisher-Porter bottle was evacuated
4. 4
   workup.ADDITIONfilled with 70 psi of H2
5. 5
   기타The volatiles were removed under reduced pressure
6. 6
   workup.DISSOLUTIONa sample dissolved in D2O
7. 7
   workup.ADDITIONTo this was added 20 μl of trimethylsilylpropionate standard solution

실험 절차

NAD+ (34.0 mg, 38.0 μmol) was placed in 2 mL of a 0.1 M phosphate buffer containing 0.07 M sodium iodide. The pH of this solution was adjusted to 8.1 with NaOH and then placed in an 80 mL Fisher-Porter bottle. The Fisher-Porter bottle was evacuated and refilled with argon three times then [Cl2Ru(TPPTS)2]2 (7.7 mg, 2.9 μmol) was added under a flow of argon. The Fisher-Porter bottle was evacuated and filled with 70 psi of H2 and stirred to 23° C. for 13.0 hr. The volatiles were removed under reduced pressure and a sample dissolved in D2O. To this was added 20 μl of trimethylsilylpropionate standard solution. 1H NMR integration shows that 7.4 μmole of NADH have been produced under these conditions.

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