반응 #1245768
ord-569e825a99124359a311268fb0ca2d73
반응 방정식
4′-chloro-3-methoxy-biphenyl-4-carboxylic acid methyl ester
H2O
LiOH
→
desired compound
수율 91.0%
4′-chloro-3-methoxy-biphenyl-4-carboxylic acid
수율 91.0%
용매
반응 조건
상세 조건
See reaction.notes.procedure_details.
후처리
- 1온도The resulting suspension is heated
- 2온도to reflux for 2 hours
- 3온도The reaction is cooled
- 4농축concentrated under reduced pressure
- 5여과the resulting solid is collected by filtration
- 6세척washed with H2O
실험 절차
To a solution of 4′-chloro-3-methoxy-biphenyl-4-carboxylic acid methyl ester, 30, (0.615 g, 2.22 mmol) in THF (20 mL) and H2O (5 mL) is added LiOH (0.932 g, 22.2 mmol). The resulting suspension is heated to reflux for 2 hours. The reaction is cooled and concentrated under reduced pressure. The crude product is acidified using conc. HCl and the resulting solid is collected by filtration, washed with H2O to afford 0.532 g (91% yield) of the desired compound as a grey solid. 1H NMR (400 MHz, CDCl3) δ ppm 10.69 (1H, br s), 8.26 (1H, d, J=8.1 Hz), 7.53-7.58 (2H, m), 7.44-7.50 (2H, m), 7.33 (1H, dd, J=8.1, 1.6 Hz), 7.20 (1H, d, J=1.3 Hz), 4.17 (3H, s). HPLC-MS: m/z 263 [M+H]+.