반응 #1245751
ord-a71312a5fd6b4db58b6c20e3e5d11696
반응 방정식
4′-chloro-3-methoxy-biphenyl-4-carboxylic acid methyl ester
H2O
LiOH
→
desired product
수율 91.0%
4′-chloro-3-methoxy-biphenyl-4-carboxylic acid
수율 91.0%
용매
반응 조건
상세 조건
See reaction.notes.procedure_details.
후처리
- 1온도The resulting suspension is heated
- 2온도to reflux for 2 hours
- 3온도The reaction is cooled
- 4농축concentrated under reduced pressure
- 5여과the resulting solid is collected by filtration
- 6세척washed with H2O
- 7기타dried
실험 절차
To a solution of 4′-chloro-3-methoxy-biphenyl-4-carboxylic acid methyl ester, 8, (0.615 g, 2.22 mmol) in THF (20 mL) and H2O (5 mL) at room temperature is added LiOH (0.932 g, 22.2 mmol). The resulting suspension is heated to reflux for 2 hours. The reaction is cooled and concentrated under reduced pressure. The crude product is acidified using conc. HCl and the resulting solid is collected by filtration washed with H2O and dried to afford 0.532 g (91%) of the desired product as a grey solid. 1H NMR (400 MHz, CDCl3) δ ppm 10.69 (1H, br s), 8.26 (1H, d, J=8.1 Hz), 7.53-7.58 (2H, m), 7.44-7.50 (2H, m), 7.33 (1H, dd, J=8.1, 1.6 Hz), 7.20 (1H, d, J=1.3 Hz), 4.17 (3H, s). HPLC-MS: m/z 263 [M+H]+.