反応 #90556

反応方程式

13

6-methoxy-5-morpholino-2,3-dihydro-1H-inden-1-one

nicotinaldehyde

NaOH

→

(E)-6-methoxy-5-morpholino-2-(pyridin-3-ylmethylene)-2,3-dihydro-1H-inden-1-one

溶媒

MeOH H2O

chloroform

反応条件

後処理

1. 1
   洗浄washed with water (3×25 mL)
2. 2
   乾燥The organic layer was dried over sodium sulphate
3. 3
   濃縮concentrated
4. 4
   その他to get the crude, which
5. 5
   その他was purified through flash chromatography
6. 6
   洗浄The compound 242 was eluted at 30% ethyl acetate in hexane

実験手順

To a solution of 13 (0.1 g, 0.404 mmol) in MeOH/H2O (1:1) was added nicotinaldehyde 241 (0.052 g, 0.484 mmol) and NaOH (0.032 g, 0.808 mmol). The reaction was stirred at RT for 6 h, diluted with chloroform and washed with water (3×25 mL). The organic layer was dried over sodium sulphate and concentrated to get the crude, which was purified through flash chromatography by using 100-200 mesh silica gel. The compound 242 was eluted at 30% ethyl acetate in hexane to afford yellow coloured solid (E)-6-methoxy-5-morpholino-2-(pyridin-3-ylmethylene)-2,3-dihydro-1H-inden-1-one 242.

出典