反応 #70199

反応方程式

alcohol

1-(2-Iodo-5-isopropoxy-4-methoxyphenyl)ethanol

→

2′-Iodo-5′-isopropoxy-4′-methoxyacetophenone

溶媒

ethyl acetate hexane

反応条件

実験手順

Concentration of fraction B (Rf 0.6 in 1:1 v/v ethyl acetate/hexane) afforded the starting alcohol 6 (200 mg, 19% recovery) as a pale-yellow oil that was identical, as judged by 1H NMR spectroscopic analysis, with authentic material.

出典