Réaction #77793

Équation de réaction

NaOH

NaCNBH3

5-(6-Fluoro-1H-indol-5-yl)-pent-4-yn-1-ol

water

→

5-(6-Fluoro-2,3-dihydro-1H-indol-5-yl)-pent-4-yn-1-ol

Rendement 73.0%

Solvants

AcOH TFA

Conditions de réaction

Traitement

1. 1
   Extractionextracted with EtOAc
2. 2
   SéchageDrying of the combined organic layers with MgSO4, evaporation of the solvent, and chromatography on silica gel with CH2Cl2/MeOH 49:1

Mode opératoire

A solution of 109 mg (0.5 mmol) 5-(6-Fluoro-1H-indol-5-yl)-pent-4-yn-1-ol in 3 ml AcOH/TFA 2:1 was cooled to 0° C., treated with NaCNBH3 and stirred for 1 hour at room temperature. The mixture was poured into icy water, made strongly alkaline by the addition of 2M NaOH, and extracted with EtOAc. Drying of the combined organic layers with MgSO4, evaporation of the solvent, and chromatography on silica gel with CH2Cl2/MeOH 49:1 gave 80 mg (73%) of 5-(6-Fluoro-2,3-dihydro-1H-indol-5-yl)-pent-4-yn-1-ol as a colorless oil, MS: 220 (MH+).

Source