Réaction #640542

Équation de réaction

lithium aluminum hydride

ethyl 6-(tert-butyloxycarbonylamino)nicotinate

magnesium sulfate

sodium hydroxide

→

desired product

Rendement 89.2%

6-(tert-Butyloxycarbonylamino)-3-pyridylmethanol

Rendement 89.2%

Solvants

diethyl ether

tetrahydrofuran

tetrahydrofuran

water

water

Conditions de réaction

Traitement

1. 1
   workup.ADDITIONAfter the addition
2. 2
   Températurecooled to 0° C.
3. 3
   workup.STIRRINGstirring
4. 4
   workup.WAITcontinued for 30 minutes
5. 5
   Autrethe solids removed via filtration
6. 6
   Concentrationthe filtrate concentrated under reduced pressure

Mode opératoire

To 4.6 mL (4.6 mmol) of a 1M solution of lithium aluminum hydride in diethyl ether at −40° C. under a nitrogen atmosphere, was added a slution of 618 mg (2.3 mmol) of ethyl 6-(tert-butyloxycarbonylamino)nicotinate from part B in 40 mL of anhydrous tetrahydrofuran. After the addition, this was warmed to room temperature, stirred for 3 hours, cooled to 0° C., and 145 μL of water, 145 μL of 20% sodium hydroxide solution and 290 μL of water were successively added. To the resulting mixture was added 50 mL of tetrahydrofuran and stirring continued for 30 minutes. Anhydrous magnesium sulfate was added, the solids removed via filtration and the filtrate concentrated under reduced pressure to afford 460 mg of the desired product, m/e=224(M+), which was used directly in the next step.

Source