Réaction #417924

ord-ee97116ffb3d4ffe8071e8b03e6f1be5

Équation de réaction

[Na+].[OH-]
sodium hydroxide
CCCCCC/C=C\CCCOc1ccccc1C(=O)OC
29
CCCCCC/C=C\CCCOc1ccccc1C(=O)OC
methyl 2-(undec-4Z-enyloxy)benzoate
CCCCCC/C=C\CCCOc1ccccc1C(=O)O
yellow oil
Rendement 99.5%
CCCCCC/C=C\CCCOc1ccccc1C(=O)O
2-(undec-4Z-enyloxy)benzoic acid
Rendement 99.5%

Solvants

Conditions de réaction

Conditions détaillées
See reaction.notes.procedure_details.

Traitement

  1. 1
    TempératureThe solution is refluxed for 24 hours
  2. 2
    AutreAfter evaporating off the solvent
  3. 3
    Extractionextracted with DCM

Mode opératoire

500 μL of 1 N sodium hydroxide solution (500 μmol) are added portionwise to 80 mg of 29 (263 μmol) in methanol (3 mL). The solution is refluxed for 24 hours. After evaporating off the solvent, the reaction medium is acidified with 0.5 N HCl and extracted with DCM. 76 mg of a yellow oil are obtained, i.e. a yield of 99%.

Source

DOI: 10.6084/m9.figshare.5104873.v1Brevet: US08877684B2uspto-grants-2014_11